10t^2+60t+6=0

Solution for 10t^2+60t+6=0 equation:

10t^2+60t+6=0

a = 10; b = 60; c = +6;
Δ = b2-4ac
Δ = 602-4·10·6
Δ = 3360
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3360}=\sqrt{16*210}=\sqrt{16}*\sqrt{210}=4\sqrt{210}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-4\sqrt{210}}{2*10}=\frac{-60-4\sqrt{210}}{20}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+4\sqrt{210}}{2*10}=\frac{-60+4\sqrt{210}}{20}
$